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Evaluate if a number is considered a happy number in the least amount of characters? [closed]

Asked by
Fifkee 2017 Community Moderator Moderation Voter
4 years ago
Edited 4 years ago

For more clarification, a number is happy when the sum of the square of all numbers within a given number is equal to 1. If you enter a loop when calculating the happy number, that means the number is unhappy. :(

Print statements are not part of your character count. Your code should explicitly state if the number is happy or otherwise.

Example: 19 -> (1^2 + 9 ^2) = 82 -> (8^2 + 2^2) = 68 -> (6^2 + 8^2) = 100 ->(1^2 + 0^2 + 0^2) = 1. This means that 19 is a happy number.

Shortest and most valid answer within a week gets the solution. If you've gotten an answer on the Discord, you are not a valid contester. I'll update the question with my implementation within due time.

And, before you prepare your moderation voter hammer, it's in-line with all rules and regulations. I checked thrice.

Cheers.

My answer:

local t,y,b,x={},tonumber,29;function h(n)if(t[n])then;return(false)end;t[n]="";b=0;for _ in(tostring(n):gmatch('%d'))do;b=b+(y(_)or(0))^2;end;if(b<=1)then;return("")end;print(b)return(h(b))end;print(h(b)~=false)

Locked by JesseSong

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Why was this question closed?

1 answer

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1
Answered by
User#23252 26
4 years ago
Edited by JesseSong 4 years ago

Please provide explanation with your answers. Simply posting code does not spread knowledge of integral scripting processes which helps people understand the logic and reasoning behind your answer.

I did it: here is my solution.

function isHappy(originalNumber)
    local pattern = {};
    function calculate(number)
        local squaredSum = 0;
        for num in tostring(number):gmatch("(%d)") do --parses a number to individual digits
            squaredSum = squaredSum + (tonumber(num) ^ 2) 
        end

        ------------uhhhhhhh------------
        if(not pattern[tostring(squaredSum)]) then
            pattern[tostring(squaredSum)] = 0;
        end
        pattern[tostring(squaredSum)] = pattern[tostring(squaredSum)] + 1;
        ---------EEEEEEEE------------
        if(squaredSum == 1) then
            return true
        elseif(pattern[tostring(squaredSum)] > 1) then
            return false
        else
            return calculate(squaredSum)
        end
    end

    local _isHappy  = calculate(originalNumber)
    if(_isHappy) then
        print(originalNumber, " is happy (:")
    else
        print(originalNumber, " is sad ):")
    end
end

isHappy(10) --happy
isHappy(12) --sad
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