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Table does not working with table.find condition?
Hi, i have make a list of a boss in my server, when a player attack a boss i want to check if the specific boss is in the list, i have make this:
local list = {
"Fox",
"Yeti",
"Crocodile",
"Pharaoh"
}
When the player attack the boss i have this condition:
if table.find(list, HitParent) then
print("Rangeboss")
HitParent = the name of the boss when the player attack, so for exemple HitParent = Fox
But the print is’nt fire ^^ maybe my condition is not exactly, somebody have a solution for check the name of the boss in the list ?
1
It's probably not the table.find part, maybe it's something else with your code? Try posting the whole thing so we can check if there's an error somewhere that's causing it to not print. killerbrenden 1537 — 4y
3 answers
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1
Use a for loop to search if the item is in the array. For example, you can do something like this:
for i,v in pairs (list) do
if v == hitParent then
print("Hit boss")
end
end
Hope this helped!
0
Not Working, the print isn't fire :/ Thorngard 4 — 4y
0
for i,v in pairs (list) do if v == hitParent then print("Hit boss") else print("Not on the list") end end AlexTheCreator 461 — 4y
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0
for this to work, HitParent must be a string value and you can do this:
for i,v in pairs(list) do
if v == HitParent then
print"hello"
end
end
0
also table.find() does not exist in lua floppybeann 0 — 4y
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if list[HitParent] then print(HitParent) end