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Is there an easier way to make crafting recipes?
Hello, I am making a survival game and it has a crafting table. I found a way to make it function but I believe there could be an easier way, let's say I could make recipes within an array. Is this possible?
Current code [LocalScript]
01 | local sl1 = script.Parent.Slot1.Item |
02 | local sl2 = script.Parent.Slot2.Item |
03 | local sl3 = script.Parent.Slot3.Item |
04 | local sl4 = script.Parent.Slot4.Item |
05 | local result = script.Parent.ResultImage |
06 | local ingreds = { |
07 | "Sticks", |
08 | 'Logs', |
09 | 'Rocks', |
10 |
11 | } |
12 |
13 | while wait() do |
14 | --CraftingTable |
15 | if sl1.Value == ingreds[1] and sl2.Value == ingreds[1] and sl3.Value == ingreds[1] and sl4.Value == ingreds[1] then |
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u could make the slots in a table also? IcyMizu 122 — 5y
1 answer
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Not sure if this is gonna work... but it could be made like that
01 | local slots = {script.Parent.Slot1.Item.Value,script.Parent.Slot2.Item.Value,script.Parent.Slot3.Item.Value,script.Parent.Slot4.Item.Value} |
02 | local recipes = { |
03 | ["campfire"] = {"sticks","sticks","sticks","sticks"}; |
04 | ["baseball bat"] = {"rocks","logs","logs"}; |
05 | } |
06 |
07 | for thingThatWillBeCrafted, ingredients in pairs(recipes) do |
08 | for i = 1, #ingredients do |
09 | if slots[i] == ingredients[i] then |
10 | done[i] == true |
11 | end |
12 | end |
13 | if #done == #ingredients then |
14 | print("crafted ".. thingThatWillBeCrafted) |
15 | else |
16 | print("nothing") |
17 | end |
18 | end |
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Didn't work unfortunately. I'll give you an update if I somehow altered it to make it work AntoninFearless 622 — 5y