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0
If all table values are not equal to?
Basically my script looks like this right now:
local foundpart = "x"
local parts = {
"a",
"b",
"c",
"d",
"e",
}
for i = 1, #parts do
if parts[i] ~= foundpart then
print("not found")
end
end
But this script will print "not found" 5 times, I want it to just print it once.
If I use break or return it will not check all the strings in the 'parts' variable.
0
use debounce? IcyMizu 122 — 4y
1 answer
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2
You can use a dictionary instead.
local foundpart = "x"
local parts = {
["a"] = true,
["b"] = true,
["c"] = true,
["d"] = true,
["e"] = true,
}
if not parts[foundpart] then
print ( "not found")
end
or table.find()
local foundpart = "x"
local parts = {
"a",
"b",
"c",
"d",
"e",
}
if not table.find(parts, foundpart) then
print ( "not found")
end