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why is my printing, chatlogs script not working as i intended?

Asked by

raid6n 2196

5 years ago

01function onChatted(msg, recipient, speaker)
02    local source = string.lower(speaker.Name)
03    msg = string.lower(msg)
04    if msg then
05        print(speaker.Name.. msg)
06    end
07end
08 
09function onPlayerEntered(Player) 
10 
11    Player.Chatted:Connect(function(msg, recipient)
12        onChatted(msg, recipient, Player)
13    end)
14end
15 
16onPlayerEntered()

The script will go like this: First, the Player will talk. Second, it should print the username and the message. Example: raid6n: Can you be my friend?

The script doesn't work with an output of: 18:07:59.288 - ServerScriptService.Script:11: attempt to index local 'Player' (a nil value)

I don't know why it doesnt work as I defined what "Player" is in line 9

I'm not good at this, so please send an answer if you can. This is a regular script.

2 answers

Answered by

ProbablyRiley 0

5 years ago

thats hard maybe a local script and use local Player = game.Players.LocalPlayer it maybe work try putting at line 10

I’ll see what happens. raid6n 2196 — 5y

ok btw thanks for helping with my other questions ur a great friend ProbablyRiley 0 — 5y

no problem also it works now thanks raid6n 2196 — 5y

have a great day raid6n 2196 — 5y

View all comments (34 more)

have a great day raid6n 2196 — 5y

bruh ProbablyRiley 0 — 5y

big lag SoftlockedUnderZero 668 — 5y

oop sorry raid6n 2196 — 5y

Jesus crist- raid6n 2196 — 5y

stack overflow moment SoftlockedUnderZero 668 — 5y

lmao ProbablyRiley 0 — 5y

Answered by

SoftlockedUnderZero 668

5 years ago

Line 16. If you don't a value in an argument of an executed function, it will default to nil.

Here's an example.

1local function A_1(b)
2    if a==nil then
3        print('argument "b" is nil')-- printed
4    end
5end;
6 
7A_1()

yeah i think that would work ProbablyRiley 0 — 5y

why is my printing, chatlogs script not working as i intended?

2 answers

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