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My Instance GUI will not show when image button is clicked, why?

Asked by

IProgram_CPlusPlus 58

5 years ago

Edited 5 years ago

Hi! I'm pretty new to scripting ROBLOX Lua however I am fluent in other programming languages including: C, C++, Java, and Python.

I have a script inside of an image button and I am trying to make it so that when you click the image button a new GUI will popup on the screen. My problem is not getting making a new frame because I check the explorer and it has made a new frame where I wanted it, the problem is that I can't see the frame or it's content! Here is the scripts contents:

local py = script.Parent

local function buttonClicked()
        local frame = Instance.new("ScrollingFrame",game:GetService("StarterGui").GuiMain)
        frame.Position = UDim2.new(0.368, 0,0.151, 0)
        frame.Size = UDim2.new(0, 416,0, 455)
        frame.ZIndex = 3
        frame.Visible = true
        local ide = Instance.new("TextBox",frame)
        ide.MultiLine = true
        print('clicked')
end

py.MouseButton1Click:Connect(buttonClicked)

2 answers

Answered by

Nefarioum 162

5 years ago

Hey there.

Everything in your code works fine, the only issue is that you are trying to parent the new Frame into the StarterGui directory of GuiMain - although it may seem like it should go there, whenever a client joins the server, everything from StarterGui is replicated over to LocalPlayer.PlayerGui.

So to fix your code, all you need to do is use script.Parent.Parent. This will automatically set the directory to the PlayerGui and saves you needing to declare the player and the service. If you had wanted to take the LocalPlayer route you can declare the LocalPlayer (in a Local Script only) through

local Player = game.Players.LocalPlayer

Personally, I find it much easier to create a GUI using the studio editor, then setting the "Visible" property to false and when they click the button turn it true. It saves the hassle of having to create a GUI through a script . Feel free to ask anymore questions if need be.

I've left a sample of the fixed code below:

local py = script.Parent

local function buttonClicked()
    local frame = Instance.new("ScrollingFrame", script.Parent.Parent)
    frame.Position = UDim2.new(0.368, 0,0.151, 0)
    frame.Size = UDim2.new(0, 416,0, 455)
    frame.ZIndex = 3
    frame.Visible = true
    local ide = Instance.new("TextBox",frame)
    ide.MultiLine = true
    print('clicked')
end

py.MouseButton1Click:Connect(buttonClicked)

Now when I click the image button the frame shows up but not the other components, why is that IProgram_CPlusPlus 58 — 5y

Hey, I'm not on my PC to test for you but my best guess would be because you altered the Z-index. Try removing that line or adding a line to alter the Z-index of the other components. Nefarioum 162 — 5y

Works, thanks! IProgram_CPlusPlus 58 — 4y

Answered by

Azure_Kite 885

5 years ago

Here is your problem

       local frame = Instance.new("ScrollingFrame",game:GetService("StarterGui").GuiMain)

You are trying to parent the frame to your StarterGui.GuiMain

StarterGui is a container that holds all the Gui that will be cloned into the player's PlayerGui on spawn (unless set to not do so)

So instead of parenting it in the GuiMain that is in StarterGui, parent it to the GuiMain that is in PlayerGui instead

you can get this, by getting first getting the player,

local player = game.Players.LocalPlayer

Did you know you can get the local player that way if you used local script? Its a really useful and convenient

Also i suggest using local script if you havent done so, for Gui

now change the previous piece of code into this

     local frame = Instance.new("ScrollingFrame",player.PlayerGui.GuiMain)

That should fix your problem

My Instance GUI will not show when image button is clicked, why?

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