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how do i make a GUI pop up after a certain amount of time?

Asked by
ChippyX 2
4 years ago
Edited 4 years ago

i'm working on a fnaf parody game. i've got a time system (12-6 am) working and that's good and all, but i really need a way for a GUI to become visible once the time hits 6 am (360 seconds irl) to be like a 'you won' screen. i've tried wait commands and stuff, but i'm still kind of struggling. i'm also not very sure if i need to put the GUI wait script into the GUI itself or into workspace? (i'm new to scripting lol, i'm srry if this sounds dumb.)

i'll appreciate it if anyone can help! :) <3

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Use a for loop, this is a mess programmerHere 371 — 4y

5 answers

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Answered by
ForeverBrown 356 Moderation Voter
4 years ago

Could just do something like this..

local gui = script.Parent.ScreenGui.Frame

gui.Visible = true
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thanks! do i put this in StarterGui or workspace? <3 ChippyX 2 — 4y
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StarterGui ForeverBrown 356 — 4y
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thank uuu :) ChippyX 2 — 4y
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Answered by
hoth7 45
4 years ago 
local GUI = script.Parent.(gui name here)
--// Try this
while true do
wait(360)
script.Parent.GUI.Visible = true
--// And make it invisible again after a certain time
wait(5)
script.Parent.GUI.Visible = false
end
--// This may work idk
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Answered by
Gameplayer365247v2 1055 Moderation Voter
4 years ago

not an answer to ur answer but pls dont repeat yourself in this way, make a variable for the text so it could look like this

local text = script.Parent.Text
while true do
    text  = "12 AM"
    wait(59)
    text  = "1 AM"
    wait(59)
    text  = "2 AM"
    wait(59)
    text  = "3 AM"
    wait(59)
    text  = "4 AM"
    wait(59)
    text  = "5 AM"
    wait(59)
   text  = "6 AM"
    end
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thank u!! this helps <3 ChippyX 2 — 4y
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Answered by
BryanFehr 133
4 years ago

I mean you could just use a wait;

local gui = script.Parent

wait(5)
gui.Visible = true
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Answered by
C0_RRUPTED 2
4 years ago 
local gui = script.Parent
gui.Visible = false
wait(360)
gui.Visible = true

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