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What is wrong with this code here? try to check if brickcolor is equal to lime green.

Asked by

5 years ago

script.Parent.ClickDetector.MouseClick:Connect(function()

if(game.Workspace.Light_Stat_1.BrickColor == BrickColor.new("Lime green"))then

    print("hi2")

    local Lift1 = Instance.new("Part")

    Lift1.Parent = game.Workspace

    Lift1.Shape = "Cylinder"

    Lift1.Anchored = true

    Lift1.CanCollide = true

    Lift1.Size = Vector3.new(7.75, 12.06, 10.04)

    Lift1.Position = Vector3.new(-89.933, 3.925, 215.561)

    Lift1.Name = "Lift1"

    end

    end)

So it sure be like when you click it check for lime green then runs the code down below that. vortex767 20 — 5y

Try using "BrickColor.new(1020)" BashGuy10 384 — 5y

You mans a genuis vortex767 20 — 5y

use this for colors: https://developer.roblox.com/en-us/articles/BrickColor-Codes BashGuy10 384 — 5y

One Question how would i loop this untill it is that color? vortex767 20 — 5y

1 answer

Answered by

karlo_tr10 1233

5 years ago

Your BrickColor isn't Lime green because I just tested with part and works for me:



if game.Workspace.Part.BrickColor == BrickColor.new("Fossil") then
    print("Test")
end
-- Prints Test

This is the only answer that makes sense. His conditional statement is just fine. It may not be visually appealing but the syntax is right. Unhumanly 152 — 5y

Ya but it is a button i made so when i press it it check if it is lime green then mades a part but it starts as really red vortex767 20 — 5y

What is wrong with this code here? try to check if brickcolor is equal to lime green.

1 answer

Answer this question