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Part Generation

Asked by
alibix123 175
11 years ago

Say I wanted to generate 100 2x2x2 parts in a square perfectly fitting together. I started with a for loop and generated 100 2x2x2 parts, but I'm not sure what to do from there.

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Answered by
Avros 5
11 years ago
01local CurrentPos = Vector3.new(0, 0, 0)
02 
03for i = 1, 100 do
04    wait(0.1)
05    local Part = Instance.new("Part", Workspace)
06    Part.Anchored = true
07    Part.Size = Vector3.new(2, 2, 2)
08    CurrentPos = CurrentPos + Vector3.new(2, 0, 0)
09    Part.Position = CurrentPos
10    if i % 10 == 0 then
11        CurrentPos = Vector3.new(0, 0, CurrentPos.Z+2)
12    end
13end

The above would do as you require.

The modulus operator, %, is used to return the remainder of the division between two given numbers. In this case I'm using it in an if statement to check if something is a multiple of ten, when it is it starts a new line on the Z-axis (allowing for a 10x10 square).

The rest is pretty self explanatory.

0
But you aren't using the modulus operator at all? Bubby4j 231 — 11y
0
As Waffle pointed out in his reply, it's apparently eaten if there are no spaces. I've edited what I posted. Avros 5 — 11y
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Answered by
1waffle1 2908 Trusted Badge of Merit Moderation Voter Community Moderator
11 years ago
1for x=0,9 do
2    for y=0,9 do
3        local e=Instance.new("Part")
4        e.FormFactor="Symmetric"
5        e.Size=Vector3.new(2,2,2)
6        e.Position=Vector3.new(x,0,y)*2
7        e.Parent=workspace
8    end
9end

or if you only want one for loop:

1for i=0,99 do
2    local e=Instance.new("Part")
3    e.FormFactor="Symmetric"
4    e.Size=Vector3.new(2,2,2)
5    e.Position=Vector3.new(i % 10,0,math.floor(i/10))*2
6end
0
apparently you have to add spaces to use the modulus operator on this website or it eats it. 1waffle1 2908 — 11y
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Answered by 11 years ago

Are you trying to copy me?!

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Copy? Was this question asked before? If it has, apologies, I didn't know. alibix123 175 — 11y

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