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how would i round up instead of down with math.floor?
local num = 10.6
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math.floor(num + 0.5) User#26971 0 — 5y
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If this helped, be sure to put [Solved] in the title so that people know you don't need any more help. User#26971 0 — 5y
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You can also use string.format to round to any place: local function round(x, n) return tonumber(string.format("%."..n.."f", x)) end User#26971 0 — 5y
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Aether, > = math.floor(0.5) = 0, math.ceil(0.5) = 1 KDarren12 705 — 5y
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you're forgetting about ceil KDarren12 705 — 5y
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Did you actually read my comment...? User#26971 0 — 5y
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math.floor(0 + 0.5) -> 0, math.floor(0.2 + 0.5) -> 0, math.floor(0.5 + 0.5) -> 1, and, finally, math.floor(0.9 + 0.5) -> 1. User#26971 0 — 5y
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It works exactly as math.round would work if it existed (math.floor(num + 0.5), that is). User#26971 0 — 5y
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Did you not read what he wrote,, KDarren12? TheeDeathCaster 2368 — 5y
1 answer
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2
You could use math.ceil().
local num = math.ceil()
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That rounds up to 1 even if the number is, say, 0.3. That's not technically rounding. User#26971 0 — 5y
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I would downvote this answer, but it's not entirely inaccurate (and there's a chance it is what he was looking for). User#26971 0 — 5y
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k whtver KDarren12 705 — 5y
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It IS the answer to his question. math.ceil() rounds up instead of down like math.floor(). If he asked how to round to nearest number, then that would be a different story. sleazel 1287 — 5y