How to roundify numbers?
I currently have this part of the script that awards the winner points and xp based on how much time the round had left, however if the round ends with a time left of like 264, the winner will be rewarded 26.4 points and 8.2 xp. How could I remove the decimals from the numbers?
hidepointer = game.ReplicatedStorage.MapTimeTotal.Value - game.ReplicatedStorage.MapTimeLeft.Value
hidepoints = hidepointer / 10
hidexp = hidepoints / 2
game.ReplicatedStorage.PlayerData:FindFirstChild(v.Name).Points.Value = game.ReplicatedStorage.PlayerData:FindFirstChild(v.Name).Points.Value + hidepoints
game.ReplicatedStorage.PlayerData:FindFirstChild(v.Name).XP.Value = game.ReplicatedStorage.PlayerData:FindFirstChild(v.Name).XP.Value + hidexp
2 answers
I think what you're looking for is math.floor().
math.floor() returns the integer version of the given floating-point number (decimal). That decimal is truncated by math.floor(), which means that if, say, the decimal was 16.7, it would round down to 16.
There is another function of the math library called math.ceil() which, by looking at its name, you can tell rounds a floating-point number up instead of down. 16.x rounds up to 17, where x is either any digit except 0 or any number of digits except 0.
Back to math.floor(). If you want to round up with this function instead of math.ceil(), you would have to add the number being floored by 0.5:
local number = 3.4 print(math.floor(number + 0.5)) -- Prints 3
Do note, however, that this ensures proper rounding with the function. This means that 3.4 rounds to 3 but 3.7 rounds to 4.
You could use this little function if you want to round values.
function round(x)
return math.floor(x + .5)
end
But if you want to remove decimals you can simply use math.floor(x) which removes all decimals.