I'm trying to add commas to integers, for example:
x = 5000 print(x) --> 5000
I want commas in between each three digits. So I want it to be:
x = 5000 function commas(str) return #str % 3 == 0 and str:reverse():gsub("(%d%d%d)", "%1,"):reverse():sub(2) or str:reverse():gsub("(%d%d%d)", "%1,"):reverse() end -- you need convert the value to string (using tostring()) print(commas(tostring(x)))
I know I'm a little bit late, but I figured I'd show my take at converting a number to comma format. This works with negative numbers as well.
function ConvertNumber(num) local newNum = nil--This variable is the final product, and will be what prints to the output local numRev = string.reverse(num)--The first of the reversed numbers local numRev2 = string.reverse(num)--The second of the reversed numbers local stringLen = string.len(num) local amntOfTimes = stringLen / 3 --This divides the string length by 3, which is also how many spaces are in between commas. local tempAmntOfTimes = tostring(amntOfTimes)--This plays into the function below if string.len(tempAmntOfTimes) == 1 then--This function checks to see if the integer value of amntOfTimes is a decimal or whole number. If it is a whole number it subtracts one from the value. This is so there isnt a comma at the beginning of the number amntOfTimes = amntOfTimes - 1 end local x = 3--This value is how many spaces the next comma needs to be local n = 0--This value offsets the comma to be in the correct spot for i = 1, amntOfTimes do numRev = string.sub(numRev, 1, x+n)..','..string.sub(numRev2, x+1, stringLen)--Everything comes together here n = n + 1 x = x + 3 end local newNum = string.reverse(numRev)--ReReverses the number to make it look normal print(newNum) end ConvertNumber(5000)--Put the number you want to convert here