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2
i don't know whats wrong it wont go the the random position how do i fix?
Please provide more explanation in your question. If you explain exactly what you are trying to accomplish, it will be much easier to answer your question correctly.
1 | local char = player.Character |
2 | local hands = {char.LeftHand,char.RightHand} |
3 | local q = Instance.new("BodyVelocity") |
4 | local xclone = game.Lighting:WaitForChild("fireball"):Clone() |
5 | xclone.Parent = workspace |
6 | xclone.Position = math.random(1,#hands.Position) |
1
Position takes a vector3 value. Theswagger66 54 — 5y
0
Position takes a vector3 value. Fifkee 2017 — 5y
2 answers
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1
Create 3 values for X,Y, and Z.
1 | local z = math.Random(1,#hands.Position) |
2 | local x = math.Random(1,#hands.Position) |
3 | local x = math.Random(1,#hands.Position) |
4 | xclone.Position = vector3.new(x,y,z) |
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0
you cannot random a vector3 value because it has 3 values in it.
so what you can do is,
xclone.Position = hands.Position + Vector3.new(math.random(-10, 10), 0, math.random(-10,10))
you can change all the 10s to whatever you like. but be careful of y, if you set too low, it may fall out of the world.