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1
how to put a cooldown on Tween?
Hello!
I would like to know how I can put a timeout in the time that the block is to return to where it was.
when the interpolation ends at the indicated position when I activated the option "Reverse" (true) It does not wait for 1 second and returns to the position it was in. How can I make him wait a few seconds and then go back to where he was?
Script:
local Part1, Part2 = script.Parent.PartA, script.Parent.PartB;
local tweenInfo = TweenInfo.new(
2,
Enum.EasingStyle.Linear,
Enum.EasingDirection.Out,
0,
true,
2
)
local a = TweenService:Create(Part1, tweenInfo, {Position = Vector3.new(81, 5, 197)})
local b = TweenService:Create(Part2, tweenInfo, {Position = Vector3.new(99, 5, 203)})
while wait()do
a:Play()
b:Play()
end
0
use a wait(1) greatneil80 2647 — 5y
1 answer
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1
If you want the part to go back after a certain timeout, you will need to split tween to 2 separate tweens:
local Part1, Part2 = script.Parent.PartA, script.Parent.PartB;
local tweenTime = 2
local cooldown = 2
local tweenInfo = TweenInfo.new(
tweenTime,
Enum.EasingStyle.Linear
)
local aStartingPosition = Part1.Position
local bStartingPosition = Part2.Position
local a = TweenService:Create(Part1, tweenInfo, {Position = Vector3.new(81, 5, 197)})
local aReverse = TweenService:Create(Part1, tweenInfo, {Position = aStartingPosition})
local b = TweenService:Create(Part2, tweenInfo, {Position = Vector3.new(99, 5, 203)})
local bReverse = TweenService:Create(Part2, tweenInfo, {Position = bStartingPosition})
while wait() do
a:Play()
b:Play()
wait(tweenTime + cooldown)
aReverse:Play()
bReverse:Play()
wait(tweenTime + cooldown)
end
Just remeber that playing a tween does not yield the thread, so you need to add tween time to cooldown time, before playing reverse tween.