Why doesn't my table of names work in for my admin script and how do I fix it?
I have a script here and it doesn't work for some reason. It is suppose to confirm if your an admin or not. I wonder what is wrong with my script
local UserName = {"InsertNameHere","voidofdeathfire"}
game.Players.PlayerAdded:Connect(function(player)
print(player.Name)
if player.Name == UserName then
while true do
wait(1)
print("ADMIN")
end
end
end)
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2 answers
Here's the easier way:
It isn't where you have to type the exact player name with the correct capitalization. It allows you to just type it like, for example, Johny. You can type it like JoHnY and it still counts as a player name.
But I still recommend using user Ids in case of a user changing their username.
local administratorList = {}
local function checkAdministratorStatus(player)
local loweredPlayerName = string.lower(player.Name)
for _,Administrator in next,administratorList do
local loweredAdministratorName = string.lower(player.Name)
if loweredPlayerName == loweredAdministratorName then
return true
end
end
end
User Id Version:
local administratorList = {}
local function checkAdministratorStatus(player)
for _,Administrator in next,administratorList do
if player.UserId == Administrator then
return true
end
end
end
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You are comparing a single string to a table. What you need to do is compare the contents inside the table (strings) with the username string. There are two ways to do this:
Firstly is a "for loop" with a regular table:
local Administrators = {
"Player1",
"Player2"
}
game.Players.PlayerAdded:Connect(function(player)
for _, adminName in pairs(Administrators) do
if player.Name == adminName then
print("Administrator")
end
end
end)
Another alternative is to use a dictionary:
local Administrators = {
["Player1"] = true,
["Player2"] = true
}
game.Players.PlayerAdded:Connect(function(player)
if Administrators[player.Name] then
print("Admin")
end
end)
This works because if the key (player name) exists in the dictionary of Administrator names, it will evaluate to true. If not, it will evaluate to nil
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