Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
2
Formatting numbers
I'm not sure if there is a way to format numbers so you can have a max of 2 decimal places. Any help is appreciated. Thanks.
EDIT: I realize I could simply do the math, then make it a string and use substring to shorten it to two decimal points and store it in a string instead of a number, but I was wondering if there was a more efficient way of doing this.
2 answers
Log in to vote
3
A simple way is to use math.floor with some easy math.
1 | function RoundToPlace(Num, Place) |
2 | return math.floor(Num * (10^Place)) / (10^Place) |
3 | end |
4 |
5 | print(RoundToPlace(1/3, 2)) --> 0.33 |
6 | print(RoundToPlace(1/3, 5)) --> 0.33333 |
7 | print(RoundToPlace(5, 2)) --> 5 |
Log in to vote
1
You can by using string.sub! Here's how:
01 | local num = 5.4547784 |
02 |
03 | function getDec(n) |
04 | local temp = tostring(num) |
05 | local dec = 0 |
06 | for i=1,string.len(temp) do |
07 | if string.sub(temp, i, i) == '.' then |
08 | dec = i |
09 | break |
10 | end |
11 | end |
12 | if dec ~= 0 then |
13 | return tonumber(string.sub(temp, 1, dec+2)) |
14 | else |
15 | return num |
16 | end |
17 | end |
18 |
19 | print(getDec(num)) |
EDIT ON YOUR EDIT: This method will work no matter where the '.' is. 500.323 or 3.232
EDIT #2: Fixed it so it won't mess up on numbers without a decimal.
1
Lol, I literally posted a second before you about substring. If there isn't an answer that has a better way, I will accept this. Trewier 146 — 11y
1
I really appreciate the thought and work you have put into this, but 18cwatford's answer is shorter, more efficient, and it stays in a number value. Upvoted because it was still a great answer. Trewier 146 — 11y