Im trying to figure out if there is any way to compare multiple values to one value using if statements. right now the only way I know how to do this takes a long time and im wondering if i can shorten the amount of code I use.
local comparative = false local table = {Box1,Box2,Box3,Box4,Box5} for i = 1,#table do if(NewBox.Name == table[i].Name)then comparative = true end if(comparative == true)then print("NewBox is the same as one of the old boxes") else print("NewBox is not the same as any of the boxes") end
Here is the code that I don't know if it works or not.
if(slot.Name == "Box"..{1,2,3,4,5})then print("slot is an equiping spot") end
This answer's to be used as a reference
Perhaps the answer to your question's to use a dictionary
? A dictionary is a table with set indexes and values, vs arrays where they have numbers for their index (to put simply). An example for a dictionary would be.
local Boxes = { -- Dictionary example ["Box1"] = true; -- `Box1` is the index, and `true` is the value for said index ["Box2"] = true; -- etc ["Box3"] = true; -- etc } if Boxes[Box.Name] then -- Checks to see if the name's in the table, and if it is... print('Box found!') -- Print that there was! :D else -- If not... print('No such box found!') -- Nothing! D: end
Stuff touched on
Dictionaries
- As the dev hub states, "a set of key/value pairs".If you have any questions, please let me know. :) I hope this helped! :D