Scripting Helpers is winding down operations and is now read-only. More info→
Log in to vote
0
How to simplify numbers like 36 into three 10s and one 6?
This question has been solved by the original poster.
Hi, I have been trying to turn stuff like 30 into three 10s or 45 into four 10s and one 5.
I have tried with the code below which doing numbers like 30 work, but numbers like 15 only print the 10 out.
function turnNumberToMoney(n)
if n < 10 then
return n
end
local nums = {}
repeat wait()
if n ~= 10 then
if n > 10 then
table.insert(nums,10)
n = n - 10
else
table.insert(nums,n)
break
end
else
if n == 10 then
table.insert(nums,10)
end
if n == 5 then
table.insert(nums,5)
end
break
end
until n < 10
return nums
end
local num = turnNumberToMoney(15)
for i,v in pairs(num) do
print(v)
end
0
This is a pretty standard interview question, so plenty of stuff will come up if you Google it: https://www.geeksforgeeks.org/find-minimum-number-of-coins-that-make-a-change/ fredfishy 833 — 5y
0
in LUA code? the8bitdude11 358 — 5y
0
whenever i look it up i get stuff about decimals the8bitdude11 358 — 5y
0
math.floor(36/10) + math.floor(36 - (36/10) /5)? brokenVectors 525 — 5y
1 answer
Log in to vote
0
I got it working for numbers under 1000
function convert10(num)
local str = tostring(num)
local n1,n2 = str:sub(1,1),str:sub(2,2)
local tab = {}
for i = 1,tonumber(n1) do
table.insert(tab,10)
end
table.insert(tab,n2)
return tab
end
function convert100(str)
local num = tostring(str)
local n1,n2,n3 = num:sub(1,1),num:sub(2,2),num:sub(3,3)
local tab = {}
for i = 1,tonumber(n1.."0") do
table.insert(tab,10)
end
for i = 1,tonumber(n2) do
table.insert(tab,10)
end
table.insert(tab,n3)
return tab
end