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How to simplify numbers like 36 into three 10s and one 6?
This question has been solved by the original poster.
Hi, I have been trying to turn stuff like 30 into three 10s or 45 into four 10s and one 5.
I have tried with the code below which doing numbers like 30 work, but numbers like 15 only print the 10 out.
01 | function turnNumberToMoney(n) |
02 | if n < 10 then |
03 | return n |
04 | end |
05 | local nums = {} |
06 | repeat wait() |
07 | if n ~= 10 then |
08 | if n > 10 then |
09 | table.insert(nums,10) |
10 | n = n - 10 |
11 | else |
12 | table.insert(nums,n) |
13 | break |
14 | end |
15 | else |
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This is a pretty standard interview question, so plenty of stuff will come up if you Google it: https://www.geeksforgeeks.org/find-minimum-number-of-coins-that-make-a-change/ fredfishy 833 — 6y
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in LUA code? the8bitdude11 358 — 6y
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whenever i look it up i get stuff about decimals the8bitdude11 358 — 6y
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math.floor(36/10) + math.floor(36 - (36/10) /5)? brokenVectors 525 — 6y
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I got it working for numbers under 1000
01 | function convert10(num) |
02 | local str = tostring(num) |
03 | local n1,n2 = str:sub(1,1),str:sub(2,2) |
04 | local tab = {} |
05 |
06 | for i = 1,tonumber(n1) do |
07 | table.insert(tab,10) |
08 | end |
09 | table.insert(tab,n2) |
10 | return tab |
11 | end |
12 |
13 | function convert100(str) |
14 | local num = tostring(str) |
15 | local n1,n2,n3 = num:sub(1,1),num:sub(2,2),num:sub(3,3) |
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