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How do I detect if an unanchored part is unable to move because it is crushed in place?
Is there some event that can help detect if the part is not moving not because it is anchored, but because it is stuck in place by friction or unable to feasibly move elsewhere
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I like this question. Hopefully someone is able to help you. DinozCreates 1070 — 6y
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nein TheluaBanana 946 — 6y
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here is an easy way, though i cant assure u it will not lag ur game:
place in part that u want to monitor
01 | local part = script.Parent |
02 |
03 | local frames = 0 |
04 |
05 | while true do |
06 | local p1 = part.Position |
07 |
08 | wait(1 / 60) |
09 |
10 | if p1 == part.Position then |
11 | frames = frames + 1 |
12 |
13 | print(frames) |
14 |
15 | else |
16 | frames = 0 |
17 | end |
18 | end |
what this does is it forever checks if the part's position, waits for a frame, then compares the previous position to the new position, all while checking if the part is uncanchored as well. If the 2 positions are the same, then it will add 1 to the frames which the part is inactive for.
Another way would be to use the propertyChanged thing, very much like the first one, but not as good in my eyes due to some inconsistencies with the thing:
01 | local part = script.Parent |
02 | local frames = 0 |
03 |
04 | local changed = false |
05 |
06 | function addFrames() |
07 | while true do |
08 | if part.Anchored == false and changed == false then |
09 | wait(1 / 60) |
10 |
11 | frames = frames + 1 |
12 |
13 | print(frames) |
14 |
15 | else |
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.Changed doesnt fire on busy properties such as position Gey4Jesus69 2705 — 6y