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How can I set all players team fifty fifty at once?
This question has been solved by the original poster.
Hi. I am trying to make a code. When It's executed, It makes half of the players in red team, other half of the players in blue team. How can I do it?
Here is an example. (It's example only. It isn't working)
01 | function setTeams() |
02 | local firstHalf = someCode |
03 | local secondHalf = someOtherCode |
04 | for i, v in pairs(firstHalf) do |
05 | v.TeamColor = BrickColor.new('Bright red') |
06 | v:LoadCharacter() |
07 | end |
08 | for i, v in pairs(secondHalf) do |
09 | v.TeamColor = BrickColor.new('Bright blue') |
10 | v:LoadCharacter() |
11 | end |
12 | end |
As I said, It's just an example. It isn't working.
How can I do it?
1 answer
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I did it. It basically uses 1 variable.
01 | local red = true |
02 | for i, v in pairs(game.Players:GetChildren()) do |
03 | if red == true then |
04 | v.TeamColor = BrickColor.new('Bright red') |
05 | red = false |
06 | elseif red == false then |
07 | v.TeamColor = BrickColor.new('Bright blue') |
08 | red = true |
09 | end |
10 | v:LoadCharacter() |
11 | end |
It simply does 1 red, 1 blue, 1 red, 1 blue .........
Thanks everybody.
1
put [SOLVED] in your question title DeceptiveCaster 3761 — 6y
0
It’s not going to be random though... GetChildren() returns an array sorted by Instances that were parented first. If you run it multiple times most players will probably be in the same team as they were previously. Rheines 661 — 6y