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How can I set all players team fifty fifty at once?
This question has been solved by the original poster.
Hi. I am trying to make a code. When It's executed, It makes half of the players in red team, other half of the players in blue team. How can I do it?
Here is an example. (It's example only. It isn't working)
function setTeams()
local firstHalf = someCode
local secondHalf = someOtherCode
for i, v in pairs(firstHalf) do
v.TeamColor = BrickColor.new('Bright red')
v:LoadCharacter()
end
for i, v in pairs(secondHalf) do
v.TeamColor = BrickColor.new('Bright blue')
v:LoadCharacter()
end
end
As I said, It's just an example. It isn't working.
How can I do it?
1 answer
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2
I did it. It basically uses 1 variable.
local red = true
for i, v in pairs(game.Players:GetChildren()) do
if red == true then
v.TeamColor = BrickColor.new('Bright red')
red = false
elseif red == false then
v.TeamColor = BrickColor.new('Bright blue')
red = true
end
v:LoadCharacter()
end
It simply does 1 red, 1 blue, 1 red, 1 blue .........
Thanks everybody.
1
put [SOLVED] in your question title DeceptiveCaster 3761 — 5y
0
It’s not going to be random though... GetChildren() returns an array sorted by Instances that were parented first. If you run it multiple times most players will probably be in the same team as they were previously. Rheines 661 — 5y