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How can I call a function from a function which is above the function?

Asked by

StrategicPlayZ 58

6 years ago

Edited 6 years ago

In my script there are many functions. I want to call one function from the other, but the problem is that the function which will be calling another function is above the function it will be calling, and not below it so it is giving me errors. You might be saying to switch the places, but in my script there are a lot of functions, and if I switch the places of the functions then the other functions will have the same problem! Please tell me how I can make this work.

Here is the script:

01local Gui = function()
02    -- Code here
03    timeLimit() -- It errors here
04end
05 
06local startRound = function()
07    -- Code here
08    Gui()
09end
10 
11local timeLimit = function()
12    -- Code here
13    startRound()
14end
15 
16game.Players.PlayerAdded:Connect(startRound)

As you can see I am trapped in this situation. I don't know how to make it possible for the top function to be able to call the bottom function. Any type of help is appreciated!

im pretty sure you can call the function below anyways, even if it hasnt technically been declared yet. ive never done it, but try and see if it works Gey4Jesus69 2705 — 6y

3 answers

Answered by

User#5423 17

6 years ago

Edited 6 years ago

You simply need to a forward declaration so that each function knows about the variable.

Example 1

01-- declare variables
02local Gui, startRound, timeLimit 
03 
04Gui = function()
05    -- Code here
06    timeLimit() 
07end
08 
09startRound = function()
10    -- Code here
11    Gui()
12end
13 
14timeLimit = function()
15    -- Code here
16    startRound()
17end
18 
19game.Players.PlayerAdded:Connect(startRound)

Though often you can reorder your functions to work around this problem.

You can also use a table to solve this.

01local f = {}
02 
03f.Gui = function()
04    -- Code here
05    f.timeLimit() 
06end
07 
08f.startRound = function()
09    -- Code here
10    f.Gui()
11end
12 
13f.timeLimit = function()
14    -- Code here
15   f.startRound()
16end
17 
18game.Players.PlayerAdded:Connect(f.startRound)

The problem is this will be recursive.

Hope this helps.

Thanks! StrategicPlayZ 58 — 6y

But wait... I thought it would work but it didn't. It says that passed value is not a function. StrategicPlayZ 58 — 6y

The code works for me. Check that this error is not from another script / line of code. User#5423 17 — 6y

Now it worked! Thanks! StrategicPlayZ 58 — 6y

Answered by

MrOpScripter 81

6 years ago

roblox needs to load the function in first but this is still possible:

01local Gui = function()
02    -- Code here
03end
04 
05local startRound = function()
06    -- Code here
07end
08 
09local timeLimit = function()
10    -- Code here
11end
12 
13while wait(1) do
14    -- put these in the order you want
15    timeLimit()
16    startRound()
17    Gui() 
18end

or if you are just firing it once:

01local Gui = function()
02    -- Code here
03end
04 
05local startRound = function()
06    -- Code here
07end
08 
09local timeLimit = function()
10    -- Code here
11end
12 
13Gui()
14startRound()
15timeLimit()

hope this helped it my first ever post :)

but otherwise i dont think you can call a function from another function that's above sorry MrOpScripter 81 — 6y

I dont want to fire all of them at once. I want to fire one of them which will fire another which will fire another. StrategicPlayZ 58 — 6y

then just do in time limit code Start round and in that Gui MrOpScripter 81 — 6y

Answered by

CaptainD_veloper 290

6 years ago

Try to put all your functions on the top, then the code that calls those functions below.

How can I call a function from a function which is above the function?

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