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Why is this New Years Timer printing 1970 and not 2019?
I'm making a New Year Countdown timer but my whole script is completely off. When I try to print this code it prints out the year as 1970 and not 2019 and I have no clue why this is happening.
local new_years_date = os.time({
year = 2019;
month = 1;
day = 1;
hour = 0;
minute = 0;
sec = 0;
})
local diffTime = os.difftime(new_years_date, os.time())
local tab = os.date('!*t', diffTime)
for k, v in pairs(tab) do
print(k, v)
end
OUTPUT: (look at the year)
hour 10 min 17 wday 7 day 3 month 1 year 1970 sec 44 yday 3
0
I answered this question iiDev_Hunt3r 64 — 5y
1 answer
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0
You put
local diffTime = os.difftime(new_years_date, os.time())
when you don't need to because new_years_date is already os.time . So here's the working script that prints the correct dates you want it to.
local new_years_date = os.time({
year = 2019;
month = 1;
day = 1;
hour = 0;
minute = 0;
sec = 0
})
local diffTime = os.difftime(new_years_date)
local tab = os.date('!*t', diffTime)
for k, v in pairs(tab) do
print(k, v)
end