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Can one add probability to math.Random()?
For example, can you make math.Random(1,10) have a higher probability to choose 1-5, rather than the same probability for all the numbers (1-10)?
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This is a really good question. I'm looking forward to seeing what the answer is. This is the most elegant solution that I could think of, and I'm not even sure it works properly: https://pastebin.com/3XEv1ziw SummerEquinox 643 — 6y
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idk if there’s a better way but like SummerEquinox’s example you could always make a “tree” where if the number falls in between a certain range then X else if then Y. Maybe there’s a more sophisticated method using randomseed and some imaginative seed? ABK2017 406 — 6y
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Ah, I would think it would be a helpful math function for everyone, but I doubt roblox would ever implement something like it. Stephenthefox 94 — 6y
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There are a lot of different distribution functions that a random variable can take - could you be a bit more specific as to how you'd like it to look? fredfishy 833 — 6y
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I'm just thinking that there should be a way to make it more likely that math.Random() will choose a certain number or set of numbers, but still have a chance to chose the rest (just less likely to). Stephenthefox 94 — 6y
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1
I dont know if you can add probability to a a math.random, but you can use it to make probabilistic events:
01 | local gen = math.random(1,100) |
02 |
03 | if gen <= 10 then |
04 | -- 10% chances |
05 | elseif gen >= 10 and gen <= 30 then |
06 | -- 20% chances |
07 | elseif gen >= 30 and gen <= 60 then |
08 | -- 30% chances |
09 | elseif gen >= 60 and gen <= 100 then |
10 | -- 40% chances |
11 | end |
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I know, but even then, the number is "random". Stephenthefox 94 — 6y
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Add another math.random inside the ifs, for example: you could add a math.random(1,5) to a 40% and a math.random(6,10) to a 10%, using the same variable Nickzus 24 — 6y