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How to make a Value like 1000 to 1K into a text ?
So I've been trying to make A Value like a cash from 1000 to 1K into a text button and I don't know how, now why I need it? To money display gui to make it shorter
Here my script :
1 | while wait() do |
2 | game.Players.LocalPlayer.PlayerGui.ScreenGui.Frame.TextLabel.Text = "Cash:" .. game.Players.LocalPlayer.leaderstats.Cash.Value |
3 | end |
2 answers
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01 | function sortText(num) |
02 | local values = {{1000, "K+"}, {1000000, "M+"}, {1000000000, "B+"}} |
03 | local str = "" |
04 | if type(num) ~= "number" then num = tonumber(num) end |
05 | for i = 1, #values do |
06 | if num >= values[i][1] then |
07 | str = (math.floor(num / values[i][1]))..values[i][2] |
08 | end |
09 | end |
10 | return (num < 1000 and num or str) |
11 | end |
This should do the trick. You can add more if you'd like, but I doubt you'd need to go above a billion.
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But how I make it into the text? brodski40 8 — 6y
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It already comes in text, you would just have to call the function. ObscureIllusion 352 — 6y
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I'm not entirely sure on that, I've tried before to see if there was a better algorithm myself, but this is the best I can think of for Simple
01 | local placeTables = {1000, 10000, 100000, 1000000} |
02 | local placeLetter = { |
03 | [placeTables[1, 3]] = "k"; |
04 | [placeTables[4]] = m; |
05 | }; |
06 | local player = game:GetService("Players") |
07 | local guiLabel = Player.LocalPlayer.PlayerGui.ScreenGui.Frame.TextLabel |
08 | local cashValue = Player.leaderstats.Cash.Value |
09 | while guiLabel do |
10 | if cashValue = placeTables[1,4] then |
11 | for_,Letter in ipairs(placeLetter) do |
12 | if cashValue == Letter then |
13 | guiLabel.Text = "Cash: "..cashValue..Letter |
14 | end |
15 | end |
16 | end |
17 | end |
There's a high probability this won't work;/
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Did this not work? User#25448 0 — 6y
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No. This code is completely invalid. User#6546 35 — 6y
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"There's a high probability this won't work;/", Sorry, brains fried rn, at least i tried right, I knew what I was writing was bull;) User#25448 0 — 6y