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2
How do I inverse a string pattern?
For example, if:
for i in string.gmatch(str, "//")
will search for "//" in the string, how would i do the opposite so it returns every part of the string separated by "//"?
0
Could you try -- for i in not string.gmatch(str,"//") RedDuck765 0 — 5y
0
that would error User#24403 69 — 5y
1 answer
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1
you can use the //(.+) string pattern to get the characters after "//" excluding that, if thats what your looking for.
local str = "//hello world!"
for v in string.gmatch(str,"//(.+)") do
print(v)
end
hello world!