Table Remove not working as it should?
I have 3 tables within a table and I am trying to remove one of them. I am expected to print only "Please" and "Me" but for some reason none of the tables are being remove?
List = {["Please"] = {}, ["Help"] = {}, ["Me"] = {}}
for i,v in pairs(List) do
print(i,v)
end
table.remove(List, 2)
print("----------------------")
for i,v in pairs(List) do
print(i,v)
end
0
0
0
1 answer
Well, the reason for this is because list is a dictionary, not an array.
Arrays and Dictionaries
Arrays are tables whose indexes are integer values
I.E.
local arr = {1,32,4434,3454543}
the above example is an array because values can be retrieved by using a integer above 0 as an index:
print(arr[2])--32
Dictionaries are tables whose indexes are string values
I.E.
local dict = {["me"] = "Hello",["Jeff"] = "ding"}
the above example is a dictionary because values can be retrieved by using a string an index, also, you can use the . syntax.
print(dict["me"])--Hello print(dict.Jeff)--Ding
The table you had in your code is a dictionary and not an array
What Went Wrong
What went wrong was that you tried to remove the second value of the table list, that was a problem as list doesn't have a second value, as it is a dictionary. What you should've done was set the value corresponding with the Help index to nil :
List = {["Please"] = {}, ["Help"] = {}, ["Me"] = {}}
for i,v in pairs(List) do
print(i,v)
end
List.Help = nil -- you could also do List["Help"] = nil, that also works
print("ding")
for i,v in pairs(List) do
print(i,v)
end
0
1
0