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How to find all children with filter?
So what I mean by this is how would I find all the children named 'THIS' in this model? And if it is called 'THIS' execute this function?
I know how to find all the children of a part but don't know anything past that...
1 | local children = model |
2 | for i = 1, #children do |
3 |
4 | --if childs names is THIS then |
5 | --rest of code |
Of course, if there is a more efficient way that would be appreciated.
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Well your comment is correct already aazkao 787 — 6y
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Isn't there something like workspace _,v in pairs do? Could I use that method, and how would I? Scaii_0 145 — 6y
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Also if I am using this method how would I interact with that specific child? Scaii_0 145 — 6y
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the in pairs functions loops through all the children of the model, if you already got the table of the model's children already your code will work fine aazkao 787 — 6y
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How would I set that child as a local? Scaii_0 145 — 6y
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what does that mean User#19524 175 — 6y
1 answer
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Here I suppose you know how to get the children of the model already so i will just leave that for you to write, store it in the table i named "children"
1 | for i =1,#children do |
2 | wait() |
3 | if children[i].Name == "this" then--your if statement |
4 | print("this is found at index"..i)--this code will run if the part is named this, and shows you the index of the part in the table |
5 | else |
6 | print("this is not found at index"..i)--this code will run if the part is not named this, and shows you the index of the part in the table |
7 | end |
8 | end |
Alternatively with the in pairs loop, both will work
1 | for i,v in pairs(children) do |
2 |
3 | if v.Name == "this" then |
4 | print("this is found at index"..i) |
5 | else |
6 | print("this is not found at index"..i) |
7 | end |
8 | end |
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But what if there are multiple instances named 'this'? Scaii_0 145 — 6y
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I wanted to find a specific 'this' which has a child called 'NEWTHIS'. Scaii_0 145 — 6y
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If there are say, 2 parts named "this", and they are the first and third part of the model, then it will print it out two times and say this is found at index 1 and this is found at index 2 aazkao 787 — 6y
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CORRECTION for my above comment, it will print out this is found at index 1 and this is found at index 3, if you want to make sure "this" has a child named "newthis" just add another if statement aazkao 787 — 6y
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use the method FindFirstChild(), if you dont know what that is here is the wiki for it: https://www.robloxdev.com/api-reference/function/Instance/FindFirstChild aazkao 787 — 6y