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How to remove a value in a table without using position?
I am trying to make a randomizer that draws a number and then a button that removes a value in an array.
This is the code that is triggered by pressing the brick that picks a random number from the table.
values = {"2", "7", "0", "5", "3", "X", "X", "X"}
function draw()
script.Parent.Value.Value = values[math.random(#values)]
script.Parent.Chip.SurfaceGui.TextLabel.Text = script.Parent.Value.Value
end
script.Parent.Button.ClickDetector.MouseClick:Connect(draw)
And this is the other code that is supposed to remove the specific value. It is fired by a different brick.
function show2()
table.remove(values, 1)
game.Workspace.Digits.Two.Transparency=0.8
wait(0.05)
game.Workspace.Digits.Two.Transparency=0.6
wait(0.05)
game.Workspace.Digits.Two.Transparency=0.4
wait(0.05)
game.Workspace.Digits.Two.Transparency=0.2
wait(0.05)
game.Workspace.Digits.Two.Transparency=0
wait(0.05)
end
script.Parent.firstnumber.ClickDetector.MouseClick:Connect(show2)
The 2 will be removed and 7 will take its place. But I have another block of code that is supposed to remove 7 when I press another button.
Is this possible to do?
1 answer
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You can use this function to remove a value from a table:
function removeVal(tablee, value) -- second array is the value you want to find in the table (can be a string, object, number, etc)
for i, v in pairs(tablee) do
if v == value then
print("removing " .. tostring(value))
table.remove(tablee, i) -- 'i' is the position of the found variable in the table
end
end
end
--Example:
local Values = {"2", 7", "0", "5", "3", "X", "X", "X"}
removeVal(Values, "2")
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Thank you! gamerboy0552 0 — 6y