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How would I split teams evenly?
So I have a script, but instead of splitting the teams evenly, it puts everyone on the same team.
for i, player in pairs(game.Players:GetPlayers()) do
if rval < dval then
player.TeamColor = BrickColor.new("Bright red")
rval = rval + 1 -- you forgot to add the new player to the team value
elseif rval > dval then
player.TeamColor=BrickColor.new("Bright blue")
dval = dval + 1 -- and here too
else
How would I have this (Or a different script) split the teams evenly?
I know it would have to take each individual player, but Im 95% certain this takes all the players, instead of one at a time
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The for loop iterates to code for each player one at a time, so no problem there. Also, take out the elseif and replace it with else. That way it has somewhere to go in case they were equal. GoldenPhysics 474 — 10y
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I would recommend a simpler condition, that doesn't involve you keeping track of anything!
local players = game.Players:GetPlayers();
for i, player in pairs(players) do
if i > #players / 2 then
player.TeamColor = BrickColor.new("Bright red")
else
player.TeamColor = BrickColor.new("Bright blue")
end
end
Here, we just say the first half of players are Blue, and the second half are Red. We do this based on the index of the player in the list, so it is obvious that we are guaranteed even teams!
Also, most likely you would want to shuffle players before applying this, so that the order is fresh whenever you remake teams. You could do that with this snippet:
for n = #t,2,-1 do
-- Fisher-Yates fair shuffle algorithm
-- Adapted from RosettaCode
local k = math.random(n);
players[n], players[k] = players[k], players[n];
end