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How do I make this part with a click detector open enable a Screen Gui?
This is my current code
local clickDetector = script.Parent.ClickDetector
local function openMenu(player)
game.StarterGui.WelcomeGui.Enabled = true
end
clickDetector.MouseClick:Connect(openMenu)
I am trying to make it so when that part is clicked, it will enable a ScreenGui that I have disabled in StarterGui. I have tried it but nothing shows in Dev Console so I don't know what's wrong.
1 answer
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1
This is because the WelcomeGui is not in StarterGui. It is in PlayerGui. Seeing your script is a server script, the contents of PlayerGui cannot be accessed by the server unless the server placed it there. However, you shouldn't be doing anything GUI related on the server. Instead, use a RemoteEvent.
-- LocalScript, under your WelcomeGui
local ReplicatedStorage = game:GetService("ReplicatedStorage")
local WelcomeEvent = ReplicatedStorage:WaitForChild("WelcomeEvent")
WelcomeEvent.OnClientEvent:Connect(function()
script.Parent.Enabled = true
end)
Server script:
local ReplicatedStorage = game:GetService("ReplicatedStorage")
local WelcomeEvent = ReplicatedStorage:WaitForChild("WelcomeEvent")
local clickDetector = script.Parent.ClickDetector
local function openMenu(player)
WelcomeEvent:FireClient(player)
end
clickDetector.MouseClick:Connect(openMenu)
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0
Thanks, it fixed it. You guys are very helpful here. :) Superameno 34 — 6y