table to vector is giving 0,0,0 every time I convert it, any help?
When I try a simple convert, it fails... table to vector
1 | local t = {4,5,6} |
2 |
3 | local v = Instance.new("Vector3Value", workspace) |
4 | v.Value = Vector3.new(t) |
5 | print(v.Value) |
Instead it converts 456 into 0,0,0 when I want it to be 4,5,6
2 answers
I don't recall ever being able to use tables in the constructor for Vector3s, maybe I'm wrong, but I don't think it's there. Here's a quick workaround:
01 | local vector = {1,2,3} |
02 | function newVector(table) |
03 | if(#table == 3) then |
04 | --The table has a length of 3 and is an object array. Now let's make the vector 3 |
05 | return Vector3.new(table[1],table[2],table[3]) |
06 | end |
07 | --Return a blank vector3 as invalid parameters were supplied |
08 | return Vector3.new(0,0,0) |
09 | end |
10 |
11 | print(newVector(vector).x) |
12 | print(newVector(vector).y) |
13 | print(newVector(vector).z) |
We created a function to help make vectors, called newVector. We can now use that to make vectors whenever we want easily. Output:
1
2
3
If you need anymore help just ask! :D
Edit: To convert it to a table again to put it in a datastore, just make a function that converts it back to a table!
1 | local vector = Vector3.new(1,2,3) |
2 | function vectorToTable(vector) |
3 | return {vector.x,vector.y,vector.z} |
4 | end |
5 |
6 | print(vectorToTable(vector)[3]) |
7 | print(vectorToTable(vector)[2]) |
8 | print(vectorToTable(vector)[1]) |
Output:
3 2 1
So now all you need to do is convert it to a table and then store it in the datastore!
1
0
0
0
0
0
0
0
0
0
A table is not a valid argument for the Vector3.new constructor.
You can either give it no arguments, where it will return an empty Vector3, or you can give it 3 numbers, and it will return a Vector3 based off of those numbers.
Giving it a table is not the same as giving it 3 numbers, you are only giving it one argument of an invalid type and it is defaulting on you.
To fix this, index the table 3 times, or unpack the table to release it as 3 arguments.
1 | --option 1 |
2 | v.Value = Vector3.new(t[1], t[2], t[3]) |
3 |
4 | --option 2 |
5 | v.Value = Vector3.new(unpack(t)) |
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