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How would I extract hours from unix time?
So I'm trying to just get the hour it is(hour of the day) for example in eastern it is
6:31
as of the time posting this.
I'm trying to get the hours from unix time. Here is what I have done so far but i feel as it is innacurate and I am not sure where to go from here.
hourTime = ((tick() / 3600) % 12)
any help would be much appreciated :)
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Local User#19524 175 — 5y
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I can't decipher whether you are telling me to use a local variable or trying to tell me something else. 4d61736f6e 59 — 5y
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I'd use os.time() to get the hours. bluestreakejjp 41 — 5y
2 answers
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You're correct, (tick() / 3600) % 12 will return the correct hour of the day. The decimal places after that hour represent the percentage completed toward the next hour. In other words, the ratio of n minutes to 60. You could easily get the n minutes you're looking for by multiplying 60 by the preceding decimals...
local function getHourWithMinutes()
local hour, alpha = math.modf(tick() / 3600 % 12)
local mins = alpha * 60
return string.format("%d:%d", hour, mins)
end
print(getHourWithMinutes())
8:17
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You can get the current hour of the day by:
((tick()%86400)/3600)
An alternative is to use os.date:
local TIME = os.date(tick(), '!*t') print(TIME.hour)
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print(TIME.hour):1: bad argument #2 to 'date' (number expected, got string) DaCrazyDev 444 — 5y
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local TIME = os.date("!*t") Thundermaker300 554 — 5y