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How check if a string is nan (not a number) ?
The title explain everything.
I tried this :
1 | local V = "145" |
2 | if (V) == "number" then |
3 | print("V is a number") |
4 | else |
5 | print("V is not a number") |
6 | end |
7 | end) |
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I think you meant to use type or typeof ? User#5423 17 — 6y
2 answers
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You can use type() to get the type of a value.
1 | local V = 145 |
2 |
3 | if type(V) == "number" then |
4 | print("V is a number") |
5 | else |
6 | print("V is not a number") |
7 | end |
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worked thanks ! xJathur95x 129 — 6y
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Np :P Simnico99 206 — 6y
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You guys make no sense. Downvoting something that works? You guys have brain damage. DeceptiveCaster 3761 — 6y
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2
You can use tonumber() to check if a string can be converted to a number.
1 | local V = "145" |
2 | if tonumber(V) then |
3 | print("V is a number") |
4 | else |
5 | print("V is not a number") |
6 | end |
7 | end) |
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Thanks xJathur95x 129 — 6y
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That's really stupid. DeceptiveCaster 3761 — 6y
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Use type(). DeceptiveCaster 3761 — 6y
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tonumber is faster and requires less typing killer08932 149 — 4y