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How check if a string is nan (not a number) ?

Asked by

xJathur95x 129

6 years ago

The title explain everything.

I tried this :

local V = "145"
    if (V) == "number" then
        print("V is a number")
    else
        print("V is not a number")
    end
end)

I think you meant to use type or typeof ? User#5423 17 — 6y

Answered by

6 years ago

Edited 6 years ago

You can use type() to get the type of a value.

local V = 145

    if type(V) == "number" then
        print("V is a number")
    else
        print("V is not a number")
    end

worked thanks ! xJathur95x 129 — 6y

Np :P Simnico99 206 — 6y

You guys make no sense. Downvoting something that works? You guys have brain damage. DeceptiveCaster 3761 — 5y

Answered by

6 years ago

You can use tonumber() to check if a string can be converted to a number.

local V = "145"
    if tonumber(V) then
        print("V is a number")
    else
        print("V is not a number")
    end
end)

Thanks xJathur95x 129 — 6y

That's really stupid. DeceptiveCaster 3761 — 5y

Use type(). DeceptiveCaster 3761 — 5y

tonumber is faster and requires less typing killer08932 149 — 4y