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Is there a way to assign half of the amount of players to a certain team?
Hi, I'm trying to find a way to divide the amount of given players in half when placing them on certain teams.
This is my code:
local player = game.Players:GetPlayers()
[math.random(2,#game.Players:GetPlayers())]
player.TeamColor = BrickColor.new("Bright green")
As you can see, the obvious issue is that if the game only had 2 players, they'd both be on one team. I'm not sure how to do this, so any help is greatly appreciated.
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Maybe try checking the amount of people on both teams and if one is higher than the other, then place them on the opposite side PoePoeCannon 519 — 6y
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I'm working on the script for you, I'm almost done. Tligtre123 53 — 6y
1 answer
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1
Hey, I have made the script for you. If you have any questions, please ask me.
--Get the Player count
local playercount = #game.Players:GetChildren()
--Calculate how many players should go on the team
--Is the number even?
if playercount % 2 == 0 then
--number is even
local playersselected = 0
local toselectplayers = playercount / 2
for i, v in pairs(game.Players:GetChildren()) do
if playersselected < toselectplayers then
v.Neutral = false
v.TeamColor = BrickColor.new("Bright green")
playersselected = playersselected + 1
end
end
else
--number is odd
local playersselected = 0
local toselectplayers = playercount / 2 + 0.5
for i, v in pairs(game.Players:GetChildren()) do
if playersselected < toselectplayers then
v.Neutral = false
v.TeamColor = BrickColor.new("Bright green")
playersselected = playersselected + 1
end
end
end
1
Thank you, this worked. Ramshackles 14 — 6y
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Glad I could help you :D Tligtre123 53 — 6y
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Just a tip, you can do local toselectplayers = math.ceil(playercount/2) instead of local toselectplayers = playercount / 2 + 0.5, this will round the number up, math.floor() will round it down. jackfrost178 242 — 6y
0
Thanks! I didn't know that! Tligtre123 53 — 6y