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The start of my 'Money' system is not working correctly, any help?
1 | game.Players.PlayerAdded:connect(function(plr) |
2 | local money = Instance.new("IntValue", game.Players.LocalPlayer) |
3 | money.Value = 50 |
4 | end) |
I can't seem to figure out why this isn't working, maybe I need to user leaderstats? But I didn't think that was needed as I just need a singular intvalue to define how much money the user currently has.
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what exactly isnt working? PoePoeCannon 519 — 7y
2 answers
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Well, here it is hope this helps.
First off, a server script can't access the LocalPlayer object. Also that's not a good way to go about doing this.
I'm also adding DataStore for you so it saves it! You're welcome! XD
So do this in a Server script
01 | local startingCashValue = 0 -- Set this to what you want the player to start out with |
02 |
03 | local DataStore = game:GetService("DataStoreService") |
04 | local ds1 = DataStore:GetDataStore("MoneyDataStore") |
05 | game.Players.PlayerAdded:connect(function(plr) |
06 |
07 | local leader = Instance.new("Folder") |
08 |
09 | local cash = Instance.new("IntValue") |
10 |
11 | leader.Name = "leaderstats" |
12 | leader.Parent = plr |
13 |
14 | cash.Name = "Money" |
15 | cash.Parent = leader |
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If this is a normal script you cannot use game.Players.LocalPlayer
But that is okay because when you set up
1 | game.Players.PlayerAdded:connect(function(plr) |
you made the parameter plr
you can just do this instead
1 | local money = Instance.new("IntValue", plr) -- use plr here |
2 | money.Value = 50 |
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Also note that the parent argument in Instance.new can cause performance issues. Set the parent separately. (See https://devforum.roblox.com/t/psa-dont-use-instance-new-with-parent-argument/30296) xAtom_ik 574 — 7y
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I was using a LocalScript but thank you! IcyEvil 260 — 7y