How do I generate random hexadecimal numbers for characters?
I want to generate a random character by using hexadecimal codes (\65-90). However, whenever I use "\", Roblox says everything after is an unfinished string. If I use "\" + (lets say) 65, then it prints "\65" instead of "A". I use the second backslash to fix the error.
I'd rather not create a table with all the letters and iterate through because I find this to be more useful, given it's possible.
-- Here's what I have so far
-- This is broken because of the single backslash
local Code = {}
for i = 1, 10 do
table.insert(Code, "\" ..tostring(math.random(65, 90)))
print(Code[i])
end
Any pointers would be greatly appreciated, thank you!
1 answer
So from investigating with the lua interpreter a bit, I'm not sure that you can concatenate a string escape sequence in a lua string. Luckily there is a workaround for converting from ASCII codes like you want into characters in string.char. Just to be specific about terminology, I don't believe that these characters are represented in hexadecimal because I could not find that language anywhere. Hexidecimal is the base 16 representation of numbers.
local Code = {}
for i = 1, 10 do
table.insert(Code, string.char(math.random(65, 90)))
print(Code[i])
end
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