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How do i make a script that randomly Enables 1 script?

Asked by
theamazemanII 32
10 years ago

Im making a door that will give you a random hat and it will randomly enable one of the ten hat giver scripts but i dont know how to do that! please help!

local script1 = script.Parent.Script1
local script2 = script.Parent.Script2
local script2 = script.Parent.Script3
local script4 = script.Parent.Script4
local script5 = script.Parent.Script5
local script6 = script.Parent.Script6
local script7 = script.Parent.Script7
local script8 = script.Parent.Script8
local script9 = script.Parent.Script9
local script10 = script.Parent.Script10

while true do
    print "Help Me!!!!"

    end

1 answer

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1
Answered by
TurboFusion 1821 Moderation Voter
10 years ago

First off, put all the scripts in a table, like this:

local ScriptTable = {
    script.Parent.Script1;
    script.Parent.Script2;
    script.Parent.Script3;
    script.Parent.Script4;
    script.Parent.Script5;
    script.Parent.Script6;
    script.Parent.Script7;
    script.Parent.Script8;
    script.Parent.Script9;
    script.Parent.Script10
}

Then you would select a random element from that table, like this:

local RandomScript = ScriptTable[math.random(1,#ScriptTable)]

Finally you would enable that chosen script, like this:

RandomScript.Disabled = false

Together it should look like this:

local ScriptTable = {
    script.Parent.Script1;
    script.Parent.Script2;
    script.Parent.Script3;
    script.Parent.Script4;
    script.Parent.Script5;
    script.Parent.Script6;
    script.Parent.Script7;
    script.Parent.Script8;
    script.Parent.Script9;
    script.Parent.Script10
}
local RandomScript = ScriptTable[math.random(1,#ScriptTable)]
RandomScript.Disabled = false

Hope this helped!

0
Thanks! It really helped! theamazemanII 32 — 10y
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