Making a colour sequence that fades through colours of the rainbow?
I need to know how to make a script that can (for example) change the colour of a brick so that it will continuously cycle through the colours of the rainbow.
I'm not on about a script like this:
while true do
script.Parent.BrickColor = BrickColor.new("Really red")
wait(0.1)
script.Parent.BrickColor = BrickColor.new("New yeller")
-- etc...
I need a more in-depth script that possibly uses the Color3 property to smoothly cycle through the different hues on the spectrum of light. I've seen it done before somewhere so I know that its' possible, I just can't think of the math or wrap my head around how I would do it.
Any help would be appreciated.
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1 answer
I made a rainbow before. To make a color sequence, you need ColorSequenceKeypoint.new. The first parameter is the time, the second is the color3. Or, make an array of all your colors to use them in a trail or what you are doing. Here is what I did
function GetRainbow()
local red = ColorSequenceKeypoint.new(0, Color3.fromRGB(255, 0, 4))
local orange = ColorSequenceKeypoint.new(.221, Color3.fromRGB(255, 214, 47))
local yellow = ColorSequenceKeypoint.new(.401, Color3.fromRGB(251, 255, 6))
local green = ColorSequenceKeypoint.new(.566, Color3.fromRGB(28, 255, 26))
local blue = ColorSequenceKeypoint.new(.699, Color3.fromRGB(44, 93, 255))
local purple = ColorSequenceKeypoint.new(.897, Color3.fromRGB(255, 26, 252))
local finish = ColorSequenceKeypoint.new(1, Color3.fromRGB(255, 0, 213))
local rainbow = ColorSequence.new({red, orange, yellow, green, blue, purple, finish})
return rainbow
end
Hope this helps!
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