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How do I change objects in a table? [SOLVED]
I need this table to change each position.Y value in a table by 0.5 each time. Such as doing 5, 5.5, 6, 6.5 etc. The problem I'm facing is that the table can't run a 0.5 value, and if I do a for loop inside of a for loop (one editing the table, the other editing the position) it will loop the position changing 13 times.
01 | PathLine1Table = |
02 |
03 | {Path.Pathkey5, |
04 | Path.Pathkey6, |
05 | Path.Pathkey7, |
06 | Path.Pathkey8, |
07 | Path.Pathkey9, |
08 | Path.Pathkey10, |
09 | Path.Pathkey11, |
10 | Path.Pathkey12, |
11 | Path.Pathkey13} |
12 |
13 | for i = 5, #PathLine1Table, 0.5 do |
14 | PathLine1Table[i].Position = Vector3.new(-2.5, i, 0)``` |
15 | end |
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I'm confused as to what you're doing. If you increment by .5 then `PathLine1Table[i]` could potentially be nil.. Are you just trying to move them all at once in increments of .5? Goulstem 8144 — 7y
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You could determine whether or not PathLine1Table[i] is nil prior to attempting to manipilate it's Position. That will make it so the code doesn't error. Goulstem 8144 — 7y
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How would I determine if it is nil or not? Also, I'm trying to move them in increments of 0.5. MaleficusFreud 7 — 7y
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You're mixing up indexing the table with changing the position of the path. On line 13, PathLine1Table has values at indices 1 through 9
01 | -- Create a table using a for loop since all your entries have the same name with one number different: |
02 | local paths = {} |
03 | for i = 5, 13 do -- I'm using 5 and 13 here because you initialized your table with Pathkey5 to Pathkey13 |
04 | table.insert(paths, Path["Pathkey" .. i]) -- Path["Pathkey5"] is the same as Path.Pathkey5, so we're constructing the key based on 'i' here |
05 | end |
06 |
07 | -- If needed, put the code you want in a function so you can call it more than once |
08 | function MoveAllPathsUp(amount) -- amount should be the amount to move up |
09 | local amountVector3 = Vector3.new(0, amount, 0) |
10 | for i = 1, #paths do |
11 | paths[i].CFrame = paths[i].CFrame + amountVector3 |
12 | end |
13 | end |
14 | MovePathsUp(0.5) |
15 |
16 | -- Or if you want the first path at height 5, the next one at height 5.5, etc (assuming you want them all at x=-2.5 and z=0) |
17 | for i = 1, #paths do |
18 | paths[i].Position = Vector3.new(-2.5, i * 0.5 + 4.5, 0) -- We create a formula here based on 'i', rather than trying to make 'i' the value we want to begin with. |
19 | end |
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Thanks, it works well and I appreciate the help. MaleficusFreud 7 — 7y