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Changing all parts using if conditions and for i,v?

Asked by 7 years ago

Hi, so I'm making something that will look through whole workspace, including models, and if the parts/unions found is neon and has the Institutional white color, it will be changed to really red.

This is a small part of my script so you understand what's going on:

print("script ran")
for i,v in pairs(game.Workspace:GetChildren()) do
    if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            v.BrickColor = BrickColor.new("Really red")
        end
    elseif v:IsA("Model") then
        -- Then so on
    end
end

This is my full script:

print("script ran")
for i,v in pairs(game.Workspace:GetChildren()) do
    if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            print("Found one")
        end
    elseif v:IsA("Model") then
        for i,v in pairs(v:GetChildren()) do
            if v:IsA("Part") or v:IsA("UnionOperation") then
                if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
                print("Found one")
            end
            elseif v:IsA("Model") then
                if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            print("Found one")
        end
                elseif v:IsA("Model") then
                    if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            print("Found one")
        end
                    elseif v:IsA("Model") then
                        if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            print("Found one")
        end
                        elseif v:IsA("Model") then
                            if v:IsA("Part") or v:IsA("UnionOperation") then
        if v.BrickColor == BrickColor.new("Institutional white") and v.Material == "Neon" then
            print("Found one")
        end
                            elseif v:IsA("Model") then
                                print("Unscripted model")
        end
    end
                    end
                end
            end
        end
    end
end

1 answer

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Answered by 7 years ago

Whenever you have the same bit of code over and over again, put it in a function instead (and anything that the bits of code differ on, add an argument to the function).

Since your code needs to reference itself within part of is algorithm (that is, you have to copy and paste it forever to make it work in all cases), you need recursion (a function calling itself).

Practically the same Scripting Helpers question

I hereby propose a recursive algorithm that is more flexible than theirs (but use whatever you feel comfortable with)

function Search(where, func) -- Search through 'where' recursively and apply function 'func' to each object found
    local ch = where:GetChildren()
    for i = 1, #ch do
        func(ch[i])
        Search(ch[i])
    end
end
local red = BrickColor.new("Really red")
Search(workspace, function(obj) if obj:IsA("BasePart") and obj.BrickColor.Name == "Institutional white" and obj.Material == "Neon" then obj.BrickColor = red end end)

You really only need to use this particular Search function if you intend to do multiple different recursive searches (ex maybe in the first you're looking for these neon parts and in a completely different location in the script you need to search for wooden parts). If it's only this one case that you need, it's easier to just use the one provided in the question linked above.

0
"obj.BrickColor.Name"? BionicWind 5 — 7y
0
Yes; I expect it's slightly faster to get the .Name of a BrickColor and compare that to a string than to create a new BrickColor and compare it with obj.BrickColor. Either method works. chess123mate 5873 — 7y
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