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How would i delete the oldest part?
Im trying to make a dropper like in a tycoon but i cant get it to delete the parts right. Once the limit is reached the ore never reaches the ground. What im trying to do is it'll delete ore that has already fell.
local dropper = script.Parent.Laser.Dropper
local count = 0
local limit = 50
while true do
wait(0.1)
if count <= limit then
count = count + 1
drop = script.Parent.Ore:Clone()
drop.Position = dropper.Position + Vector3.new(-5,0,0)
drop.Parent = dropper
drop.Transparency = 0
drop.Anchored = false
drop.CanCollide = true
else
count = count - 1
ore = dropper:FindFirstChild("Ore")
ore:Destroy()
end
end
1 answer
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You could store the ores in a table, and then iterate through the table and destroy them using a for loop.
Let me know if this isn't what you're going for, so I can edit my answer :)
local dropper,count,limit = script.Parent.Laser.Dropper,0,50
local ores = {} --Table to store ores
--Function to clear ores
function clearOres()
for _,v in next,ores do
count = count - 1
v:Destroy()
wait(.1)
end
end
while wait(.1) do
if count < limit then
count = count + 1
drop = script.Parent.Ore:Clone()
drop.Position = dropper.Position + Vector3.new(-5,0,0)
drop.Transparency = 0
drop.Anchored = false
drop.CanCollide = true
drop.Parent = dropper
ores[#ores+1] = drop --Add ore to the table
else
clearOres() --Call the clearing function
end
end
0
This is close but im looking for something that deletes ores constantly instead of placing them all then removing. NinjaNickO 0 — 7y