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Can this script be reverse-engineered to find the random seed?
local digits = {'1', '2', '3', '4', '5', '6', '8', '9'} math.randomseed(os.time()) local result = digits[math.random(8)] for i = 2, 50 do result = result..digits[math.random(8)] end print(result)
--> 88854243421464255299891111895292628431988589634664
My end goal is to find what os.time() returned when this script was run. Is that feasible?
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This script uses broken math.random(). Tested. When you declare result, digits[math.random(8)] will keep returning the same number. Solution: math.randomseed(os.time()) ;math.random();math.random();math.random() Programical 653 — 7y
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https://scriptinghelpers.org/questions/42029/random-always-picks-last-element-in-table Programical 653 — 7y
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I recommend asking this on https://crypto.stackexchange.com Programical 653 — 7y