[Colors] How can I find the opposite Color?
Is there an equation/function that is available to use to calculate the opposite of a given colour (sometimes known as complementary) without having to write a massive table??
For example, the opposite of white (255/255,255/255,255/255) is black (0/255,0/255,0/255)
[EDIT]
I've tried getting the opposite using this formula, but isn't 100% efficient:
Original Color = r,g,b Opposite/Complimentary = 255-r,255-g,255-b
The opposite color is the result of 255 take away the value of its respective color.
Tested code on a TextLabel:
while true do
Redrandom = math.random(0,255)
Greenrandom = math.random(0,255)
Bluerandom = math.random(0,255)
script.Parent.BackgroundColor3 = Color3.new(Redrandom/255,Greenrandom/255,Bluerandom/255) -- Original Color
script.Parent.TextColor3 = Color3.new((255-Redrandom)/255,(255-Greenrandom)/255,(255-Bluerandom)/255) --Opposite Color
script.Parent.TextStrokeColor3 = Color3.new((255-Redrandom)/255,(255-Greenrandom)/255,(255-Bluerandom)/255) --Opposite Color
wait(math.random(1,10)/10)
end
I understand there's a different function to create a color using RGB colors up to 255, but I prefer this method.
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1 answer
From what I can tell, this method is perfectly fine, but if you're really concerned about performance, I would imagine this would be faster than all that division (division is relatively slow):
local Colour1 = Color3.new(0.5, 0.5, 1.0) -- A light blue colour. local Colour2 = Color3.new(1 - Colour1.r, 1 - Color1.g, 1 - Colour1.b) -- Probably some orange colour.
However, my main advice to you is that you should not worry about performance unless it is a really big issue. Optimising your scripts will often take more effort than it's worth and will likely increase your code's complexity.
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