I need help with team balancing?
what i want is only one player on the red team and all the other players will be at the blue team. and i dont know how to do it
if balanced then
local red = 1
team = math.random(1,2) > i edited it cause its wrong
if team == 1 then
red = red + 1
obj.TeamColor = BrickColor.new("Bright red")
elseif team == 2 then
blue = blue + 1
obj.TeamColor = BrickColor.new("Bright blue")
end
sorry if i did not explained it so well guys wat im actually doing is making teams (its a sword fighting game) and i only want Red team to have only limited players or 1 player
2 answers
Not sure what you are doing here, you are setting team to a random number between 30 and 45 then if team == 1 (impossible as it has to be 30-45) red will equal red + 1 (making it 2). Then you are saying if team is 2 (again impossible for the same reason as above) the variable blue will be made 1.
To do this you would need to use for loops in order to cycle through all players. http://wiki.roblox.com/index.php?title=Loops#For
players = game:GetService("Players"):GetPlayers()
for i,v in pairs(players) do
if red ~= 2
local red = 1
team = math.random(1,2)
if team = 1 then
red = red +1
end
else
blue = blue +1
end
end
That's probably the closest you will get with the script you are using, although that still has issues.. That is not a finished script, just some adjustments to yours.
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For me, the teams even out automatically, assuming you have an even number of teams and the server limit matches that. For example: Team Red and Team Blue, ten server max, it should work automatically. (idk if that works when hundreds of people join at the same time, the most i ever had in my game was 50)