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It is possible to call a function with the use of arithmetic?

Asked by
FoolInSpecs 35
8 years ago 
function exeC(func)
    func()
end

while true do
    for i = 1, 10 do
        LO()
        local L = "L"
        local N = i-1
        local LN = L..N
        local LNf = LN.."()"
        wait(0.01)
        print(LNf) -- Used in checking...
        exeC(LNf)
        wait(0.99)
    end
end

What I wanted to happen is to call a function with the use of arithmetic. I find it messy to call a function with lots of if statements (Assigning i value to each function). I have functions named L0 - L9. Is it possible to call a function with arithmetic to match the function's name? e.g (L0 : "L"..[i], i = 0)

I would appreciate your response/answer/help.

2 answers

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1
Answered by
IDidMakeThat 1135 Moderation Voter
8 years ago

You could put them in a table, like this:

local Functions = {L0, L1, L2, L3, L4, L5, L6, L7, L8, L9}

Then call them like this:

Functions[i]()

Where i is the index, from 1 to 10.

0
I know how to use tables but I did not know that it could work like this. Thank you for sharing this cool piece of knowledge! FoolInSpecs 35 — 8y
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0
Answered by
EchoReaper 290 Moderation Voter
8 years ago
Edited 8 years ago

You can technically get away with this by using setfenv to modify the environment of your script, but I'd recommend using a table of functions instead since modifying the script environment is pretty nasty and will also give you tons of warning squiggles.

Table of functions:

local L = {}
for i=0,9 do
    L[i] = func
end

print(L[0]())

setfenv

local env = getfenv(1)--make sure we keep track of the stuff in the current env like script/etc
env["L0"] = function() return 3 end
setfenv(1, env)

print(L0())--L0 will work, but it'll have a warning squiggle since it wasn't properly defined in the script

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