Why are both 'If' statements activating?
Admins = {} -- Up to 3 Admins
Children = {} -- Do not touch
function Children(player) -- This will turn everyone who isn't part of the list into children
local Player = player:GetFullName()
print(player)
if Player.UserID == Admins[1] or Player.UserID == Admins[2] or Player.UserID == Admins[3] then
print("DayCareWorker")
end
if Player.UserID ~= Admins[1] or Player.UserID ~= Admins[2] or Player.UserID ~= Admins[3] then
print("Child")
end
end
game.Players.PlayerAdded:connect(Children)
This is my FIRST time trying to work with a table, and I'm clearly not understanding it enough.
I haven't gotten to the big stuff, but the first IF statement is suppose to send the message Daycareworker in the output, but if that isn't true then it'll skip over that and then head to the second one in this function and print Child.
I'm doing all this to see if it works correctly.
But the only thing I'm getting in the output is : Player1 DayCareWorker
Even if I take the values out of the tables.
How do I make the correct if statement run when it's suppose to. This is all in a script, but should I put it in a local script?
2 answers
Let's begin with the first error,
- The or function,
Basically, if you have use an or statement with a conditional statement, it will check if both values are nil, and if they are, the code after doesn't run. For example,
local x = "y"
if x == "x" or x == "y" then
print("X = x or y ")
end
---------------------
OUTPUT,
X = x or y
So let's use the ~= operation. This checks if something is not something, as you probably know.
local x = "y"
if x ~= "x" or x ~= "y" then
print("X = x or y ")
end
The output would ALWAYS be the same, no matter the value of x. I hope you understand why.
Simple fix,
Use an else statement.
So if the first conditional returns false, the second knows, and can interpret the information.
Admins = {} -- Up to 3 Admins
Children = {} -- Do not touch
function Children(player) -- This will turn everyone who isn't part of the list into children
local Player = player:GetFullName()
print(player)
if Player.UserID == Admins[1] or Player.UserID == Admins[2] or Player.UserID == Admins[3] then
print("DayCareWorker")
else
print("Child")
end
end
game.Players.PlayerAdded:connect(Children)
There, now onto the
Second problem,
You're trying to access the UserId of the String, the player's name, not the player. Also, I'm not sure but I think it's userId, not UserID. That part probably doesn't matter, but I'm changing it anyways,
Admins = {} -- Up to 3 Admins
Children = {} -- Do not touch
function Children(Player) -- This will turn everyone who isn't part of the list into children
if Player.userId == Admins[1] or Player.userId == Admins[2] or Player.userId == Admins[3] then
print("DayCareWorker")
else
print("Child")
end
end
game.Players.PlayerAdded:connect(Children)
Third problem,
I don't think this is your script, but who ever you stole/took it from, sucks at scripting. I'm removing the Children variable because it has no point. Yes, I'm touching it.
Admins = {} -- Up to 3 Admins-- Which is stupid
function Children(Player)
if Player.userId == Admins[1] or Player.userId == Admins[2] or Player.userId == Admins[3] then
print("DayCareWorker")
else
print("Child")
end
end
game.Players.PlayerAdded:connect(Children)
Final Note,
I would recommend you use a loop to check if people are on the list of being an admin, because you can add as many people as you want and it would be much better overall. Also, your name is always Player/Player1 when you're testing in studio.
Good Luck!
If I helped, please don't forget to hit the accept answer button next to my answer. It helps a lot.
you used the same if twice.. It runs the same thing
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