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1
How do I make this more accurate?
function tween(part,pos,tim,stop) --stuff
local function stuff() --for the stopige
local runs = 100 --smoooth
local ToTake = runs*.03 --time it will take
if ToTake>tim then
repeat
runs=runs-1
ToTake = runs*.03
until ToTake<tim --gets closer to tim
else
repeat
runs=runs+1
ToTake = runs*.03
until ToTake>tim
end
local cf = part.CFrame --start cf
for q=runs,0,-1 do
wait()
part.CFrame = pos:lerp(cf,q/runs)
end
end
if stop then --stop! In the name of lo-o-o-ove
stuff()
else spawn(stuff)
end
end
return tween
The above is a moduleScript. The purpose of it is to smoooooothly move parts. It works fine, but if I do something like this.
p1 = game.Workspace:WaitForChild("Part")
p2 = game.Workspace:WaitForChild("Part2")
tween = require(game.ReplicatedStorage.tweens)
start = tick()
tween(p1,p2.CFrame,10,true) --it has to pause here
print(tick()-start) --print 11.3
So, does anybody know how I could improve the accuracy of the time?
1 answer
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3
You have the right idea with the lerp function. The goal here is to get a value between 0 and 1 and have it correlate to the time it should take for the entire tween to complete.
In my opinion the easiest way to do this is to get the tick when the tween is started and then find the difference in time after you wait or do a renderstep, etc.
So for example:
function tween(part, goal, finalt)
local origin = part.CFrame; -- where we start from
local start = tick(); -- the initial tick we compare to
local dt = 0; -- the change in time from initial tick until now
while dt < finalt do
dt = tick() - start; -- update out time change
part.CFrame = origin:lerp(goal, dt/finalt); -- get as percentage
wait(); -- or renderstepped, etc...
end;
part.CFrame = goal; -- set it at the end to be precise
end;
-- example
local s = tick();
tween(game.Workspace.Part, CFrame.new(), 3);
print(tick() - s);
2
Oh, thank you. I never thought about using tick() in a function before. Also, why the semi colons? theCJarmy7 1293 — 8y
3
Habit from other programming languages EgoMoose 802 — 8y