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Is there a way around this?

Asked by
wackem 50
8 years ago

Please make your question title relevant to your question content. It should be a one-sentence summary in question form.

I'm trying to make a script that can exceed the default values of a ROBLOX leaderboard, it was successful until I tried to add quadrillions, I know it's possible because I've seen games do it but every time I use the following script I get the value (only when it gets to quadrillions)

1e+.0k

This is the script: (any help is appreciated)

function ConvertShort(num, cool)
    local x = tostring(num)
    if #x >= 16 then
        local important = (#x - 15)
        cool.Value = x:sub(0,(important)).."."..(x:sub(#x-13,(#x-13))).."qd"
    elseif #x >= 13 then
        local important = (#x-12)
        cool.Value = x:sub(0,(important)).."."..(x:sub(#x-10,(#x-10))).."T"
    elseif #x>= 10 then
        local important = (#x - 9)
         cool.Value = x:sub(0,(important)).."."..(x:sub(#x-7,(#x-7))).."B"
    elseif #x >= 7 then
        local important = (#x-6)
        cool.Value = x:sub(0,(important)).."."..(x:sub(#x-5,(#x-5))).."M"
    elseif #x >= 4 then
        cool.Value =  x:sub(0,(#x-3)).."."..(x:sub(#x-2,(#x-2))).."k"
    end
end

game.Players.PlayerAdded:connect(function(plr)
    local cash = Instance.new("StringValue", plr)
    cash.Name = "cash"
    cash.Value = "0"
    cash.Changed:connect(function()
            ConvertShort(tonumber(cash.Value), cash)
    end)
end)
0
I don't have a fix for this, but I do have a working(for any size number) script to shorten the number. Do you need to use this script? Or can I answer with mine. theCJarmy7 1293 — 8y
0
you can answer with yours as long as it shortens any number wackem 50 — 8y
0
answering theCJarmy7 1293 — 8y

1 answer

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Answered by
theCJarmy7 1293 Moderation Voter
8 years ago 
local letters = {
    "K",
    "M",
    "B",
    "T",
    "QD",
    "QN",
    "SX",
    "SP",
    "O",
    "NO",
    "DEC",
    "UND",
    "DUOD",
    "TRED",
    "QUATD",
    "QND",
    "SXD",
    "SPD",
    "OD",
    "NOVD", -- I really doubt somebody will get more than a novemdecillion
    --put more here
}
local nums = {}

for q=1,#letters do
    local dig = (q*3)+1 --digits
    local letter = 1*(10^(dig-1)) --for dividing purposes
    table.insert(nums,#nums+1,letter) --insert
end

function shorten(num)
    local len = math.ceil(math.log10(num + .5)) --get the digits
    if len>=4 then --check if it's ok to shorten
        for q=1,#letters do
            local dig = (q*3)+1 --smallest number of digits the letter is
            if len <= dig+2 then --check if this digit works
                local toDo = math.floor(num/nums[q]) --the dividing number
                local newNum = toDo..letters[q] --the new num
                return newNum --return it
            end
        end
    end
end

print(shorten(1789000000000000000))--it returns the shortened num
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