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1
Instead of having a script in a part and copying, is there a way to reduce all the work needed?
What I mean is, is there a way to instead of having a script in a lava brick and copying it to other places I might want can I instead have one single script where it detects if it's touched.
like this
brick -script brick -script brick -script brick -script
is that a way to reduce this like:
brick brick brick brick Script(PARENT IS WORKSPACE)
2 answers
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2
You can put all of your lava parts in one model and do like this in one script:
1 | for i,v in next,Workspace.LavaParts:GetChildren() do |
2 | v.Touched:connect(function(hit) |
3 | --your code |
4 | end) |
5 | end |
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ahh okay, but im a little confused what the 'next ' is? yurhomi10 192 — 11y
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It basically just iterates through everything inside of the table, and the :GetChildren() method creates a table of all of the children of a model. TheGuyWithAShortName 673 — 11y
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why not just do pairs? isnt it the same? dont get me wrong, i like the answer just questioning the difference between these two commands. yurhomi10 192 — 11y
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pairs actually uses next, so it's more efficient to use next. TheGuyWithAShortName 673 — 11y
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Yup! In fact, I even think this is better in terms of efficiency and CPU usage. But let's not get technical and let's answer your question.
01 | function CreateLavabrick() |
02 | local new = Instance.new("Part", game.Workspace) |
03 | new.Name = "Laval" |
04 | new.BrickColor = BrickColor.Red() |
05 | new.Anchored = true |
06 | new.Touched:connect(function(p) |
07 | if p.Parent:FindFirstChild("Humanoid") then |
08 | p.Parent.Humanoid.Health = -1 |
09 | end |
10 | end) |
11 | return new |
12 | end |
13 |
14 | -- For example, create 100 lava bricks and move them to a random location! |
15 |
16 | for i = 1, 100 do |
17 | local lava = CreateLavabrick() |
18 | lava.CFrame = CFrame.new(Vector3.new(math.random(-100,100), 2, math.random(-100,100)) |
19 | end |