How do I find the smallest difference between 2 numbers in a table?
Basically, let's assume I have a table and a number to compare it with.
local Table = {1,2,5,8,20} local Number = 4
How do I compare the table with the number, to return the value in the table closest to the number I first provided? (In this case, it would return 5.)
Disregard the fact that if I would enter 3, for example, it would try to return 2 numbers. I'll filter the table out beforehand to remove any numbers that are lower then the provided number
1 answer
Something I came up with was,
first use a for loop that goes through all the numbers inside the Table. Then check if the current number in the Table is less than Number, if so then subtract Number with the current selected Table number. If it's greater then just do the other way around. I also made a separate table where I stored the new numbers and then I used table.sort to get them in order.
Some useful links:~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ http://wiki.roblox.com/index.php?title=Function_dump/Table_manipulation http://wiki.roblox.com/index.php?title=Loops
local Table = {1,2,5,8,20}
local Number = 4
local difference = {}
for i = 1, #Table do
if Table[i] < Number then
print(Number - Table[i])
table.insert(difference, Number - Table[i])
else
print(Table[i] - Number)
table.insert(difference, Table[i] - Number)
end
end
table.sort(difference)
for i = 1, #difference do --Just for testing
print(difference[i]) --would print out 1,2,3,4,16
end
Is this what you were after?